6t^2-2t-6=0

Solution for 6t^2-2t-6=0 equation:

6t^2-2t-6=0

a = 6; b = -2; c = -6;
Δ = b2-4ac
Δ = -22-4·6·(-6)
Δ = 148
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{148}=\sqrt{4*37}=\sqrt{4}*\sqrt{37}=2\sqrt{37}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2\sqrt{37}}{2*6}=\frac{2-2\sqrt{37}}{12}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2\sqrt{37}}{2*6}=\frac{2+2\sqrt{37}}{12}
$